(x^2+1)(2x+1)-5(2x+1)=0

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Solution for (x^2+1)(2x+1)-5(2x+1)=0 equation: 



(x^2+1)(2x+1)-5(2x+1)=0

We multiply parentheses

(x^2+1)(2x+1)-10x-5=0

We add all the numbers together, and all the variables

-10x+(x^2+1)(2x+1)-5=0

We move all terms containing x to the left, all other terms to the right

-10x+(x^2+1)(2x+1)=5

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